Recent content by BensonCa

Oh, I see what I did, thank you

Homework Statement In a certain carnival ride, visitors enter a circular room with radius r=9.1m. The room then begins spinning around its center, reaching an angular speed of 1.7rad/s. What centripetal acceleration do the riders experience? Homework Equations ac= v^2/r The Attempt at a...

Force equals mass times acceleration and are directly proportional, in increase to force on an object means an increase in acceleration. Vi is negative since the 7.10 is in a downward position and Vf is positive since it is in effect after the bounce of the ball and headed back in the upward...

Ok so what I did there is use the uam equation Vf= Vi + at where I used the force applied to the ball 67.2 as acceleration because after the bounce the change in velocity came from the force the ground applied to the ball. Then I used the 0.120s for time, took the new velocity 15.164 and divided...

Well I was completely wrong on this entire formula, so this is what I have found out. the correct area that this belongs to is dealing with the concept of simple machines. MA= li/lo and li Fi= lo Fo Fi= input force Fo= output force li= input lever lo= output lever ok so for this problem I did...

change in velocity= Vf-Vi where Vf = 15.164 (Vi + a 67.2 as force applied increase the acceleration of the ball * t 0.120s) 15.164/7.10 = 2.135 or 2.14 Change in m= m* change in V= 0.624kg * 2.14=1.33

Homework Statement A "peel" is a flat, long-handled shovel that a pizzaiolo uses to slide pizzas into and out of an oven. If a peel is 1.7m long and has a mass of 2.4kg and is carrying a pizza of mass 1.1kg as shown, what force must the pizzaiolo apply with his forward hand to hold the peel...

m* change in velocity= 4.43 I= 8.06 then I tried 8.06/4.43= 1.819/ 1.8/ 2

force * time equals impulse = 67.2N * 0.120s = 8.064, then impulse = momentum change which is m*change in V = 0.624kg * 8.06= 5.03 which I believe is wrong.

I want to say that we can apply that the ball was at rest before it was thrown but since it doesn't specifically state that the ball is at rest I'm questing if we can assume that it was. That would mean that it gives the Velocity int however I don't see how that would help solve this problem...

Thank you for your responses and assisting me in the right direction, I really appreciate it

A 0.624kg basketball is thrown straight down and strikes the floor at a speed of 7.10m/s. The floor applies an average force of 67.2N for a duration 0.120s, causing the ball to bounce back upward. How high does it bounce? ok F= 67.2N t = 120s I= change in M= 0.624 * (-7.10) since the initial...

Impulse = Change in momentum · The impulse experienced by an object is the force•time. · The momentum change of an object is the mass•velocity change. · The impulse equals the momentum change.

Homework Statement A 0.624kg basketball is thrown straight down and strikes the floor at a speed of 7.10m/s. The floor applies an average force of 67.2N for a duration 0.120s, causing the ball to bounce back upward. How high does it bounce? The Attempt at a Solution I'm not actually sure on...