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Centripetal acceleration formula

  1. Jan 9, 2016 #1
    1. The problem statement, all variables and given/known data
    In a certain carnival ride, visitors enter a circular room with radius r=9.1m. The room then begins spinning around its center, reaching an angular speed of 1.7rad/s. What centripetal acceleration do the riders experience?

    2. Relevant equations
    ac= v^2/r

    3. The attempt at a solution
    I believed that ac= v^2/r which would equal .3175824176 or .32 m/s^2

    but the answer is 26 m/s^2 and the explanation is Centripetal acceleration is given by ac=rω2. WHY?
     
  2. jcsd
  3. Jan 9, 2016 #2
    You're given angular speed, and you're trying to plug it into a formula with velocity.
     
  4. Jan 9, 2016 #3
    Good effort though! You have omega, the formula you want to be using is a = w^2 r substituting w = v/r into the original formula you have.
     
  5. Jan 9, 2016 #4
    Oh, I see what I did, thank you
     
  6. Jan 17, 2016 #5
    I would rather go with:
    v= wr
    v =1.7 x 9.1 = 15.47

    to find the acceleration:
    a = v^2/r
    a = (15.47)^2/9.1
    a = 231.32/9.1
    a = 26.299 ( and can be rounded to 26)
     
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