Recent content by Beyond3D

  1. Beyond3D

    My Grade 11 Math mark is eating me alive. What do I do?

    1st one: So does that mean I am bad at math? I am asking this as I am genuinely starting to worry.
  2. Beyond3D

    Studying How to self-study physics past High School Level?

    Schaum's textbooks, just classic.
  3. Beyond3D

    My Grade 11 Math mark is eating me alive. What do I do?

    I only did bad because it was AP, I am sure I can get 95+ in normal, academic grade 12 math next year.
  4. Beyond3D

    Wordle Lovers - Play the NYT Daily Game

    why did you have to spoil
  5. Beyond3D

    Wordle Lovers - Play the NYT Daily Game

    Must've been so frustrating man.
  6. Beyond3D

    I like physics, wish I could be an Astronaut but they need WAY too many qualifications for WAY...

    I like physics, wish I could be an Astronaut but they need WAY too many qualifications for WAY too little pay.
  7. Beyond3D

    I don't like chemistry actually, more into the math side of physics. I plan to do Astrophysics...

    I don't like chemistry actually, more into the math side of physics. I plan to do Astrophysics for a Ph.D.
  8. Beyond3D

    Wish I could, but I have chemistry 🙄

    Wish I could, but I have chemistry 🙄
  9. Beyond3D

    Geometry: Similar Shapes

    Can you give me a little nudge, just a slight hint?
  10. Beyond3D

    Geometry: Similar Shapes

    I know there are two solutions, but how would you get the second?
  11. Beyond3D

    Wordle Lovers - Play the NYT Daily Game

    struggled hard at the end ⬜⬜🟨⬜⬜ ⬜🟩🟩⬜🟩 ⬜🟩🟩⬜🟩 ⬜🟩🟩⬜🟩 🟩🟩🟩🟩🟩
  12. Beyond3D

    Engineering Physics Major Considering Masters in EE -- Need help!

    https://www.bls.gov/ooh/Life-Physical-and-Social-Science/Physicists-and-astronomers.htm I'd recommend skipping the MPhys and going to physics PhD for the most $$$.
  13. Beyond3D

    Geometry: Similar Shapes

    Yes, and that assumption is *heavily* implied graphically.
  14. Beyond3D

    Geometry: Similar Shapes

    Let me help, it is a pretty basic geometry problem if you know the rules behind it Assume that the triangles are congruent (scalable to eachother) and that the ratios between the sides remain constant $$\ AB:AE=AC:AD$$ $$\frac{8cm}{12cm}=\frac{x+8cm}{15cm}$$...
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