If you would observe only the circumference of the small disc by visualise it to be rolling then it rolls 2pie*a on the circle of radius 5a fully in one roll, I think the center moves by a distance smaller than 2pie*a
center has smaller speed than tangential point , are you refferring to the the speed of the points on the rigid body barring rotation??, if yes then we were told in class that property of rigid body is that all points of a rigid body when considering translational motion have the same speed...
what is small r that you mentioned , seeing your method
I came upon another reasoning that as @ tends to 0, then w1 tends to 0 , this discredits the first approach as w1=w/lcos@ according to the first approach
L is the distance OC=root(24)*a
As for the approach you mentioned you mentioned, I have also written that as my second approach
I couldn't understand why the the first one is incorrect
I assumed the angular velocity of the center of mass of the two discs about z axis to be w1
note that angular velocity of center of mass of both discs and center of anyone disc about z axis is same, you can verify that if you want, me after verifying it will use it to decrease the length of the...
i drew the diagram with BC horizontal component of the center of mass of the whole system in the same vertical line as the point where it is rest upon on the table, I am getting the answer same as given with a cot(alpha) instead of cos(alpha)
but the exam is such you can challenge a particular question for bonus if its a typo or its answer given is wrong, many challenged the answer as 2.05 but finally ans was not changed, it remained 2.05
I have a solution available on the internet that is doubtful to me and i have attached that...