Recent content by blaxican707

ok great, I was looking at this as common sense - but then agian this is physics and did'nt think that this answer would be that simple. I appreciate the help:smile:

I'm trying to solve that equation right now... kinda of confusing. But back to the original post - ok so if the ball reached it's peak at a horizontal distance of 12.8m, then if the trajectory of the ball is symetrical, the ball traveled 25.6m when it hit the ground - correct?

Yes horizontal velocity. So the ball reached its horizontal peak at 12.8m? I thought it was 6.4 because I had originally thought that 12.8m was the total distance the ball had traveled until it hit the ground. -9.8m/s^2 in the equation had already gave me the vertical peak correct? I looked...

my bad, the 5.0m/s is the vertical velocity and the 25.0m/s is the horizontal velocity!

Homework Statement A ball is thrown into the air with an initial vertical velocity of 5.0m/s in addition to its horizontal velocity of 25.0m/s, how far would the ball travel horizontally before it reached it's peak? Homework Equations vf = vi + at I've also tried vf = 1/2g +at...