Recent content by BluE

I used free body diagram and based on numbers that we have, I didn't get the right answer for the coefficient of kenetic friction (mu k), which should become 0.061. I can't figure out how to get to here.. it's so frusterating.. please help clearify the steps.

Hey, can you guys help me out with this... A 75 kg box slides down a 25 degree ramp with an acceleration of 3.6 m/s^2 ...what is the coefficient of kenetic friction? I know how to do the basic equation problems from what our teacher told us, but I don't know how to manipulate the...

Alright, I've gotten it. Thank you, everyone.

Yes, I've drawn a free body diagram, but I'm not sure how to solve it now. I have not solved questions using friction before. Do I need to find the x and y components and go from there?

Hi, I got stuck on this and need help... So, the given info are: theta = 10 degrees force, applied = -2.00 x 10^4 N and mew k = 0.797 gravity = 9.81 m/s^2 Is that right? Now this is where I'm stuck.. I'm not sure what I need to find first and the equations to use to find it...

Alright, I see now that it is in the fraction is reduced to the simplest form.

1.) If x and y are positive integers, and 2003x=2004y, what is the least possible value of x? Wait- 2003x=2004y x=2004y/2003 x/y=2004/2003 so x=2004 and y=2003? That makes sense...

Well, I'm not sure about the first and second, but I think I understand the third one. It looks like a trinomial squared.

What are all real solutions of a for which the sum of the squares of the roots of x^2 - 8ax + 14a^2 = 0 is 25? (This is the last piece.)

(a^2 - b^2)x^2 - (a^2 + b^2)x + ab = 0

Okay, here's a third one. I have to put it in separate pieces because it keeps sticking together in one line. 3.) a^2 - b^2 \neq 0

Let's see... I couldn't find the answers to these. They look fun- maybe you can find the solutions. 1.) If x and y are positive integers, and 2003x=2004y, what is the least possible value of x? 2.) An integral triangle is a triangle with positive side-lengths and a positive area. Such a...

What, did I say something wrong? Oh. Now I see. 14 and 16 are the amu of them. I didn't look at it.

If N=14 and and N=O/3, then 14=O/3 so O=14/3=4.66666... but you say O=16. I think I'm confused.

Ah, okay. Sorry, and thanks. And since there is no "greatest number less than one" then that means there is no "greatest number less than x" when x is equal to any real number, right?