Recent content by bman!!

its ok i spoke to a chemist and he set me straight. besides, I've already had that exam, so i can set about forgetting everything i learned ;)

Sodium, = 11, has the ground state configuration [Ne] 3s^1 and is a “one electron” atom. Magnesium, Z= 12, is a “two-electron” atom. Write down its ground state configuration and possible term values. i think i get the right answer but I am having a couple of issues: my answer: ground...

not totally sure this should be in the advanced physics section. its a general test your knowledge question of everything youve learnt, so naturally i can't remember anything... a magnet of magnetic moment U is droped such that it falls down metal tube of length L. the magnet's magnetic...

its ok, sorted. brain fart.

[SOLVED] Fourier transform of a function such that it gives a delta function. ok say, if you Fourier transform a delta function G(x- a), the transform will give you something like ∫[-∞ ∞]G(x-a) e^ikx dx a is a constant to calculate, which gives you e^ka (transformed into k space)...

ah of course, cheers that cleared it up

sorry, i need to clarify this a little bit... i meant to say, if you look at simple momentum conservation for something a bullet being fired, at first appearances momentum might seem to be 'created', this is obviously not true, and a simple analysis including BOTH the gun and the bullet clears...

... if you consider something simple momentum conservation, like in the case of a bullet, if you consider the system of the gun and the bullet, the momentum is zero before and after the shot is fired. same for collisions etc... however when you consider something like a deflection in...

ah i see now. cheers.

ah i see, that makes sense. but when would V(I) = V(R) + omega X (V(R)) be applicable? or is it just an intermediary?

i understand the reason and steps leading to the equation that relates acceleration in the inertial frame to acceleration in the rotating frame i.e. a(I) = a(R) + 2(omega)Xv(R) + (omega)X(omega) X r a(I) = acceleration in inertial frame a(R) = acceleration in rotating frame omega =...

cheers mate, I am just working through some electromagnetism, and stuff like this crops ups every half a page, where its simple to show, but still somewhat tricky, and the guy who wrote my notes, as clearly considered it trivial so he just doesn't bother showing the steps involved. Im sure...

I'm assuming J(t') is the higher inegral function (from fundamental theorem of calculus: \int_a^x f(t)dt= F(x) - F(a) where \frac{d}{dx}F(x) = f(x) i'm sorry for being really dense, but i always draw a blank with this type stuff. so you eventually end up with ∂J/∂z = ∂s/∂z times...

we are given some component of a vector potential A A = B\displaystyle\int^d_0 I(t')\,dt' where d = t -z/c and B = constant=1/2 mu0 (permeability constant) x c (speed of light) the derivation then wants me to calculate the magnetic field from this vector potential...

is the picture not working or something? its just a simple boundary (jump?) conditions problem. i say simple, I'm pretty terrible with jump conditions, so any help is really appreciated. this one step is driving me mad!