Recent content by bmandrade

Homework Statement A heart dysfunction that can cause death is ventricular fibrillation. This is an uncoordinated quivering of the heart as opposed to regular beating. An electric shock to the chest can cause momentary paralysis of the heart muscle, after which the heart will sometimes...

Ok so in this case then Fe= mg * tan 25= .098 N * tan 25= .046 N and then for the distance between you are right so the distance will be sin 25 = x / 12 x = 5.07 cm X 2 = 10 cm = .1m so plugging this new numbers the answer should be 7.15 X 10-7 coulumbs

Homework Statement Please check if i did this problem right.. two charged pith balls are suspended on very light 12. cm strings. Each has a mass of 10. . In equilibrium the total angle between the string is 50 degrees, Assuming that the pith balls are equally charged, what is the...

So i would use this P1 +m/V)gy1= P2 +(m/V)gy2 use water's density and g=10 and then for y1 would I use zero and for y2 I would use what height? what about P1?

Homework Statement Examine the schematic of the tower. Water flows in at the top to balance the water flowing out through the holes, so the height of the water in the tower stays fixed. Take state 1 at the top of the water in the tower and state 2 in the water just as it flows out of the...

so at 90 there is no torque

oh ok but still for the angle of 90 its 0 or no?

so i would have to use cos of 60 times .4

oh ok in that cas .346 m (73.5) = 25.4 N-m for angle 30 for angle 60 .173 m (73.5) = 12.7 N-m for angle 90 will it be 0 since cos of 90 = 0?

cos I will have to use the .4 m as the side of the triagle the 30 degree angle makes this way i can find the distance of the 30 degree angle by using cosine so .4 (cos 30) = .346 m using this i have to plug into the torque equation do i have to use sin of 30 or no because since the...

it would be for angle 0 right??

.4 m x 73.5 N = 29.4

ok 7.5 kg = 73.5 N also the lenth of the leg is 40 cm so .4 m

Homework Statement I need to solve a problem where a 7.5 Kg object is attached to an ankle and leg lifts are done. There is a picture that shows the leg being at rest where the angle is 0, then legs its lift to 30 degree angle, 60 and 90 degree angle I am suppose to find the torque about...

thank you! :)