bob012345's latest activity

It makes a difference for a zero ohm termination = tail. Changing the tail, the starting value for evaluation, of a 100 term ladder...

Which circuit are you simulating with 100 stages? Our original ladder in post #1 or your ladder? Not sure what you mean by “changing the...

Welcome to PF! I believe you are solving a different ladder that goes like this: The ladder being studied in this thread has the...

Here are recursion relations that give the exact polynomials for the numerator and denominator for any ladder with ##N## stages and a...

Doing that derives the limiting term as ##0.9⋅10^n## discussed in post #8.

I believe if it’s transcendental it is also irrational.

And it may be rational, irrational and if irrational it may be expressible as a compact, exact quantity involving a square root or it...

For the original infinite ladder in post #1 I have found that the number of digits in ##p## and ##q## goes as ##1+n(n-1)## as in post #5...

BTW, the reverse ladder, where the horizontal resistors are large and the vertical resistors are small, converges super fast with no...

I’m not sure what you mean. It makes a big difference what value I pick for the infinite termination. The value of ##0.9⋅10^n## is not...

The thing I find about continued fractions, and ladder attenuators, is that evaluation from right to left attenuates the numerical...

I have found that this continued fraction converges rather slowly. As ##n→∞##, the horizontal resistors become vanishingly small and the...

Thanks. In looking at the exact solutions for the first few terms it seems the fractions quickly get gigantic. These seem also to have...

Simply fixed value ladders always do converge to a recurring continued fraction, and since an RCF can be evaluated with a quadratic...