Recent content by bob4000

dy/dx - 1/ x^2 +1 + 1 / y+1.dy/dx = 1 + dy/dx =1 /x^2+1 - 1 = dy/dx(1-1/y+1) dy/dx = (x^2 + 1)^-1 - 1/ 1- (y+1)^-1

yes, that's the method i tried, but i get the wrong answer

i have a question I'm attempting as extra work, I have tried the usual method but no luck... find expressionsf for dy/dx in terms of x and y: ln(x^2+1) + ln(y+1) = x +y

i have undertaken an investigation, where the aim is to establish a relationship between the frequencies of an earthquake, and the height of the building(at maximum deflection parallel to motion). to do this, a model was created; a building of lego blocks and a vibration generator set to...

merci beaucoup

i and the rest of my class are finding it impossible to find the answer to this part of the question: find the exact value of cos A from secA-cosA=1/2 thanks in advance

thanks. i think we were all just looking at it form the wron perspective. much obliged

a)state the value of sec^2x-tan^2x b) the angle A is such that secA + tanA = 2. show that secA-tanA=1/2, and hence find the exact value of cos A. part a was a doddle so to speak, however, part b was on the contrary; it took our class half an hour, but to avail if someone could shed light...

f=ma parallel to slope 50-F-1250sinaplha=0 f=ma perpendicular to slope N-1250cosalpha=0 F=mu*N mu=0.1 N=F/mu;N=10F ; 10F-1250cosalpha=0 F+1250sinalpha=50 ps, I am half asleep so excuse any blatant stupidity

a straight footpath makes an angle of aplha with the horizontal. an object P of weight 1250N rests on footpath. the coefficient of friction is 0.1. the least magnitude of a force, acting up the footpath, which will hold the object at rest on the footpath is 50N. by treating the object as a...

if a car is moving at 14m/s, and the coefficient of friction is 0.8, what is the distance it takes to stop the car after the brakes are applied locking all four wheels?

thanks to all who contributed. keep up the good work

have drawn the diagram, but didnt really help

there is friction, which is why i don't know how to work it out (friction is unknown)

dear reader i have this query which i have not been able to tackle, even after many attempts. i have also consulted my teacher but to no avail. (by the way, this is not actually homework, just work i decided to do). a toboggan of mass 20kg is pulled, with rope, up a snow-covered hill...