Recent content by bolini

Cool! Very helpful, thanks for the link.

I'm attempting to help my son with a elementary school project that measures the impact crater of a ball at different heights. I thought it would be cool to see if we could achieve terminal velocity, but at 180 feet without considering air resistance, I think we are already too high to...

And the answer - pretty darn high. Without drag I get 55 meters using d=Vf^2 / Vi^2 +2*a with Vi being 0 and Vf being 33m/s and 'a' being 9.8 Not sure how to include resistance in the equation because it varies depending on the velocity which is changing until 33m/s is achieved.

still need help The equation for terminal velocity is the square root of 2mg/CpA. I used 9.8 m/s for gravity, .5 or the drag co on a ball and 1.29 kg/m3 for air density. So I come up with approx 33 m/s. My question now is how do I come up with the drop height necessary to reach terminal...

Can anyone help me with the terminal velocity of a lacrosse ball? Approximations would help too. Thanks.