Recent content by Branson Holt

Well to start off I plugged in everything that I had from the information given: 1/2(.0101)v^2= 1/2(97.8)(.441)^2 + F(.441) Then I found F by using F= u(coefficient of friction) x Fn(Normal Force) so F= (.554)Fn which I found normal force by using Fn= (m+M)g Fn= (.0101 + .0441)(9.8)= .53116 So...

Homework Statement A 10.1 g bullet is fired horizontally into a 44.1 g wooden block that is initially at rest on a rough horizontal surface and connected to a massless spring of constant 97.8 N/m. If the bullet-block system compresses the spring by 0.441 m, what was the speed of the bullet just...