# Recent content by Brickster

1. ### Integration using Trig Substitution

My mistake, you're right. Thanks!
2. ### Integration using Trig Substitution

Yes, I'm fairly certain that is a standard integral, and it comes out to: sin^{-1}y + C But I'm also fairly certain that I am supposed to solve this problem using the expression, substitution, and identity when I do the trig sub. Maybe I am overcomplicated the problem and should just stick to...
3. ### Integration using Trig Substitution

So I should end up with: \int sec\Theta d\Theta} Correct? then I would get ln \left| sec\Theta+tan\Theta \right| + C
4. ### Integration using Trig Substitution

as in changing the bottom from 1 + (sinx)^2 to 1 + y^2 ? I can get to: \int \frac{sec^{2}\Theta d\Theta}{\sqrt{1+tan^{2}\Theta}} But after that it makes no sense, I just get back to the original equation when I sub. again.
5. ### Integration using Trig Substitution

Homework Statement \int \frac{cosx dx}{\sqrt{1 + sin^{2}x}} Homework Equations Expression: \sqrt{a^{2} + x^{2}} Substitution: x = a*tan\Theta Identity: 1 + tan^{2}\Theta = sec^{2}\Theta The Attempt at a Solution I have tried using Trig Substitution, but I end up getting an equation much...
6. ### Trifunction Derivatives problem

The quotient Rule is: y= u/v y'= [(vu'-uv')/(v^2)] The product Rule is: y= uv y'= (vu'+uv') the chain Rule is: y=u^n y'=(n)(u^n-1)(u')
7. ### Cannon shoots a projectile

Heh, this isn't complex at all. In high school, especially since your physics class just started, you won't have air resistance. You should be able to do this easily if you read the material or listen to the teacher in class. Do you have all of your kinematic equations memorized?
8. ### Horizontal force with a crate at a 27 degree angle

The problem says at a constant speed, therefore a=0. Also, there is no friction slowing you down. F=ma, a=0, so the net force is zero. You need to find the vertical and horizontal components of the applied force. So F(applied)*cos(27)=F(applied,horizontal), and F(applied)*sin(27)=F(applied...
9. ### 7-11 store and chose three items

Matt, that made me laugh so hard. Must live in Alberta, Canada, no sales tax there.
10. ### Bonds? Where are the val. e-'s

In convalent bonds, when the atoms interact to form the bonds, where do the valence electrons, or clouds, exist. Do the simply loop around them in a chaotic figure eight of sorts, or do the electrons spin inbetween them? Is the realitive location of the the val. e-'s even know? And if the...
11. ### Time and Atoms: Can they exist without each other

PhillipF, Antihydrogen is the antimatter counterpart of hydrogen. Whereas the common hydrogen atom is composed of an electron and proton, the antihydrogen atom is made up of a positron and antiproton. There are real no differences with the reaction of matter/time as apposed to antimatter/time.
12. ### Why I don't believe. Why do you?

I got quite a laugh out of dcbobo's vague discription of a pseudo-important "thing". We do not care for "beating-around-the-bush", either get to the point, or privately torment yourself. Thanks
13. ### Memorize periodic table

Thank you Goku, links are/were helpful I personally came up with, hi-he-lie-be bokay-n-o flu-knee, thats the first 10 small abbv of the main words strung together, it works for me
14. ### Memorize periodic table

Does anyone have any interesting or easy ways to memorize the first, oh, 10 to 40 or so elements (only including the names and the abbv.)? thanks
15. ### Mechanism of Most Chemical Reactions

I just sent in my 3500 bar codes from my degree-chex cereal boxes, now I'm just waiting for the papers so its official. :)