The two equations are:
m1a = T - μm1g
m2a = Fp - T - μm2g
I solved for T as such:
T = m1a + μm1g
Substituting this T value into the second equation, I got:
m2a = Fp - (m1a + μm1g) - μm2g
So,
3a = 24 - (2a + (0.27)(2)(9.8)) - (0.27)(3)(9.8)
Solving for a, I...
Yes, I tried adding the two together by solving for T and plugging that equation into the other. Unfortunately, after crunching the numbers, I did not come to the correct answer.
Newton's Laws -- friction, tension, acceleration
A block of mass m1 = 2 kg and a block of mass m2 = 3 kg are tied together and are pulled from rest across the floor by a force of Fp = 24 N. The coefficient of friction of the blocks with the floor is μ = 0.27.
a) What is the acceleration of...