Recent content by builder_user

Hm..I think I'll don't like conductors. Inductor is in the circuit(as a wire) or is not in the circuit but conductor... I still don't know all cases. Or there is no sth(resistor for example) in parallel connection with it. Or there is no current if it series connection. Or it has a voltage...

You mean that immediately it will be look like pic.1? But I can use Laplace replace

Really?Great! But if before commutation Uc was !=0 so It would look like long time or not?

This circuits? Long time after commutation I only need to find voltage on R3?Is R4 in the circuit? Immediately after commutation I need to find current on resistor R4?

last question. How this circuit looks before & after commutation? Is my circuits correct?

Oh. 43.9=44* я used arcsin(0.72) but sin(x)=0.69 so arcsin(0.69) is needed

U=100*(0.72+j*0.69) f=arcsin(0.72)=arcos(0.69)=46* so for t=0 U=100*sin(0+46)=72?

Аh! I see. I forgot formula for amplitude. arcsin(x)=f <- phase

But if U=Umsin(w*t) t=0->sin(0)=0 and U=0

So I need to use t=0?And u(0)=0? Before commutation t=0 so U(o)=0 After commutation it will be simple circuit with DC and two resistors? And dif.equatations will be the same as in previous case right?

I can make choice?I know only t=0 and t!=0.that's all that I know about time

Yes it does

Yes of course 'cause we always use degrees.

1/0.56*3.14*j*20^-6

Hm.. My Req=(R2*1/j*w*C)/(R2+1/jwC)=998.8-35*j Req2=R1+req=1998-35*j E=200*(cos(45)+j*sin(45))=141.4+141.4*j I=E/Req2 Circuit