Recent content by buyerat

Thank you very much for the quick help. I thought I was on the right track but wanted to get some expert help :D. Thanks again

Homework Statement Point P is at the origin. Charge A is at (-3,0) and Charge B is at (4,0). What is the electric potential at point P. Let's assume they are both positive charges for now, but I am interested to know if and how it changes if either/both of the charges are negative...

Ok thanks much for your help perhaps there is a problem with the program.

so would the final answer be 21cos3x(arcsinx)+(7sin3x)/(sqrt(1-x^2)) because that does not seem to be the right answer on my web assignment i dunno

Ah yes it is I just typed it up wrong in my initial post. I can't seem to figure out the derivative though. The derivative of 7sin3x is not working out for me. I tried things like 7cos3x(3) but that doesn't seem to work. Any help would be great thanks

If f(x) = 7sin(3 x) * (arcsin(x)), find f'( x ). I'm assuming I need to use the product rule, but I am failing to set it up right. I assume it's with the beginning part and I'm just goofing up on what to do with the coefficient. I think it's ((7sin3x)' * arcsinx) + (7sin(3x) +...

I got it now thank you very much for your help.

I really can't seem to get the right answer if you wouldn't mind helping further. I seem to be coming up with 2143.35m, but that does not seem to be the answer.

Ok I don't really see why you do that, but I can figure it out hopefully. At the end you write the equation once as The average velocity 1.33 = (6440 - d)/(6440/2.6 + 2.35*d) then at the end you said 1.33 = (6440 - d)/(2477 - 2.35d) Is there some reason the signs are switched before the...

I was just looking it over but I do not understand where you pulled 2.35 from

Homework Statement In reaching her destination, a backpacker walks with an average velocity of 1.21 m/s, due west. This average velocity results because she hikes for 6.44 km with an average velocity of 2.54 m/s, due west, turns around, and hikes with an average velocity of 0.470 m/s, due...