Recent content by Calaereth

Thank you very much. This has helped me a lot. :)

I need a faster approach to solving the problem. If you know how to solve it can you show me how? If not then, I guess I can get the book.

In grade 12 and I don't have any previous knowledge on projectile motion. We haven't really covered it much in class.

I've never had a problem that is to find the initial velocity of a projectile motion and with a height at that. Let me try it out though.

So basically I have to use simple equations to solve for this such as V= d/t V = 48.76 m / 5s V = 9.75 m/s If this is not right, then can you please help me?

Previously - Horizontal Vix = V cos 32 Vertical Viy = V sin 32 I tried this: delta Y = Viy*t +0.5 * -9.8 * 5^2 Viy = (delta y - 0.5*9.8*-t^2)/t Viy = (30.48 -122.5)/5 Viy = -18.404 m/s

I didn't since I used the distances: theta = tan-1 (30.48m/48.76m) =32 degree

My teacher hasn't really taught us how to do it but gave us 5 motion equations: a = V2 - V1 / delta t delta d = 1/2 (V1 + V2) delta t delta d =V1*t + 0.5t^2 delta d = v2*t - 0.5*a*t^2 v2^2 = V1^2 + 2a*delta d I tried to find the angle using theta = tan-1(Vyf/Vxf) or theta = tan-1(dy/dx) It...

I've been trying to come up with the answer but it hasn't gotten me anywhere. I know that I need to find the angle to get the velocity. Q: A rock is projected from the edge of a 30.48 m tall building at some unknown angle above the horizontal. 5 seconds after, the rock strikes the ground at a...