Recent content by Calculex

The total charge in the system adds to 0 and the total charge between the capacitors is 0. So the charge Q on the 'outside' plate of the 10 uF capacitor is equal and opposite to the charge Q on the outside plate of the 5 uF capacitor and the charge on the inside plates (which totals 0)...

I seem to recall that Dirac looked at all this when he developed relativistic quantum mechanics. I am afraid you are barking up an old tree that Dirac has already peed on. Worth a look anyway.

Since it is DC, the charge builds up on the capacitor until the potential across the capacitor is equal to the applied voltage. The voltage drop across the capacitor is Q/C. The two parallel capacitors are equivalent to 10 uF. The total capacitance is 10/3 uF. And the charges on the 'inside'...

I don't know about actual evidence. But to the extent that electromagnetic field represents energy - such as two charges separated by a distance - it has mass = E/c^2 which has gravitational effect.

A closed organ pipe has two closed ends. An open organ pipe has one open end. The closed end means that this has to be a node or place of 0 amplitude for the standing wave. The open end means that this has to be a point of maximum amplitude. Find the length of tube in which a resonating...

If Abdus Salam was not the originator of a preon model that quarks are composites of smaller particles, he was one of a small group. You might want to read this address in which he predicts the discovery of the preon by 1990: http://nobelprize.org/physics/laureates/1979/salam-lecture.pdf

The answer to question 6 is wrong. Heat pumps do 6d) all the time. The correct answer is b). I agree with others that the answers to 1, 4, 5 and 10 are wrong and the correct answers are: 1b, 4c, 5c, (although I am confused by the word 'extracted'), and 10d. With respect to 5, Efficiency...

t is just time, of course - plotted along the horizontal axis. \omega is the angular speed in radians/sec. So \omega t is just the angular displacement in radians. Since one complete cycle or circle is 2\pi radians, \omega t = 2\pi\nu t = 2\pi t/T

To derive the solution from first principles is not trivial. But the result is that for equal masses, an elastic collision results in the masses moving with velocities at 90 degrees to each other (except for perfectly head-on collisions). That is all you have to know. (This is a very useful...

What if the electron beams flowed in opposite directions?

You can think of the principle as: forces always come in pairs - equal and opposite pairs. This is perhaps the only universal fundamental principle of all physics. It applies to Classical physics, special and general relativity, quantum physics and the Standard Model. It applies in all frames of...

I am not sure I understand your question. Are you asking how does the KE of the mass m that releases a photon change? If so, the answer lies in the momentum imparted by the photon to the mass. It imparts E/c momentum to the mass so the mass experiences a change in speed of v=E/mc

I agree. Enlightened private funding (e.g. the old Bell Labs) can support pure research and come up with innovative technologies (eg. laser, transistor). But a peer reviewed publicly supported funding mechanism for research is essential for an innovative technology sector. Great discoveries...

Thanks for this post. Very helpful. I am a little 'weak' on my understanding of the weak interaction. I am finding this thread and the "Elemenary particles presented thread to be very well done and the links are very useful. You and Marlon are doing a very good job here. (PS. I hope you...

Yes. The mass of a nucleon is about 60 times greater than the mass of the individual quarks that comprise it. There are no other real particles in there. So the additional mass has to be due to the energy of the strong nuclear force (gluon 'field'). That part I can understand. But what about...