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Projectiles (delta)(theta) = g(delta)t/V0
Projectiles...(delta)(theta) = g(delta)t/V0 I am given this problem... if the projectile is fired a short time (delta)t later, show that the angle correction is (delta)(theta) = g(delta)t/V0 where V0 is the inital speed of the projectile and by assuming that the elevations of the projectile...- calgaryleb
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- Projectiles
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- Forum: Introductory Physics Homework Help