Recent content by Camdenl
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High School Calculating the area of a circle or square using decimals
Thank you for helping me understand the concept, it really helped.- Camdenl
- Post #9
- Forum: General Math
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High School Calculating the area of a circle or square using decimals
Sorry for being rude, I fully understand now. When I visualized i thought of a square with .5cm sides and then a square that is 1cm^2. When I visualized putting the square in the .5 by .5 I realized the area only took up 1/4 of the square.- Camdenl
- Post #8
- Forum: General Math
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High School Calculating the area of a circle or square using decimals
I understand that I didn't use the correct way to show measurements, but that still doesn't help my question. Your answer is the equivalent of me asking "Are there things that shouldn't be an adverb." and you respond with "You forgot an apostrophe in 'shouldn't'."- Camdenl
- Post #4
- Forum: General Math
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High School Calculating the area of a circle or square using decimals
I came across something that is completely counter-intuitive, and I'm wondering if I'm correct or not. If a square has a side that is .8m someone would do .8 time .8 which is .64. How can an area be smaller than a side I thought and so I looked it up and found only one site that said something...- Camdenl
- Thread
- Algebra Area Circle Square
- Replies: 9
- Forum: General Math
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Undergrad Measurement standard for joules = Momentum in kilograms
Thanks for the info! -
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Undergrad Measurement standard for joules = Momentum in kilograms
So I grabbed Plancks constant for joules(6.626070040(81)×10^−34) and multiplied it by the frequency(6.8×10^15) using the google calculator it came out at 3.6496394e-16. Also, thanks for the info on nanometers. -
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Undergrad Measurement standard for joules = Momentum in kilograms
I adopted the frequency from "http://www.csun.edu/~jte35633/worksheets/Chemistry/5-2PlancksEq.pdf" and then attempted to use the formula available on that site. The probable reason for why I got my E would likely be because of my novice in this subject. Also, could you explain to me how I could... -
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Undergrad Measurement standard for joules = Momentum in kilograms
I'm sorry, but I checked for 44 nm on a wavelength chart, and it came under uv light. Did I make some mistake, or what? -
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Undergrad Measurement standard for joules = Momentum in kilograms
Oh, I got it, I just didn't understand. I'm pretty new to this stuff, sorry -
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Undergrad Measurement standard for joules = Momentum in kilograms
Thanks, I'm fairly new to stuff like this since I'm learning out of personal interest. -
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Undergrad Measurement standard for joules = Momentum in kilograms
The numbers don't have 7 decimal spots, they have 24, they're shortened. For example, 1.2173887*10^-24 is equal to 0.000000000000000012173887. The whole thing's a decimal. -
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Undergrad Measurement standard for joules = Momentum in kilograms
The "E" was in joules, and I would like to find out the momentum "p" in kilogram-meter per second. -
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Undergrad Measurement standard for joules = Momentum in kilograms
Basically, I found the energy of a photon using its frequency ((6.8*10^15) and E=(3.6496394*10^-16)) and so I then used "p=E/c" to find the momentum and got 1.2173887*10^-24 however I don't know the measurement of the momentum. Is there a better equation to use to find momentum, and what would...