Recent content by Carl_M

In #3, http://img405.imageshack.us/img405/4035/mmmcopy.png Is this what it's saying for the diagram?

Homework Statement 1. A billboard is to made with 100 m2 of printed area, with margins of 2m at the top and bottom, and 4m on each side. Find the outside dimensions of the billboard if its total area is to be a minimum. 2. A cylindrical soft drink can is to have a volume of 500 ml. If...

1. a) d/dx (( x-3)^4(2x+5)^5) = (2x+5)^5(d/dx((x-3)^4)) + (x-3)^4(d/dx((2x+5)^5) =4(x-3)^3(2x+5)^5(d/dx(x-3)) +5(x-3)^4(2x+5)^4(d/dx(2x+5)) =4(x-3)^3(2x+5)^5 +10(x-3)^4(2x+4)^4 = 0 X=3 , X = 5/9 , -5/2 How would I get the increasing/decreasing? c ) Would it be Increase on [ -oo, 5/9] and...

hints? Derivatives: Intervals, stationary points, logarithms, continuous functions Homework Statement Got any hints or anything? 1. Suppose that f(x) = (x - 3)^4 ( 2x + 5)^5 a) Find and simplify f ' ( x ) b) Find stationary points of f c) Find exactly the intervals where f is...

Homework Statement For what values of k is the line y = kx - 2 tangent to the graph of f(x) = x^2? Homework Equations The Attempt at a Solution Would I just find f'(x) = 2x?

f ' (x) = 0 So that would be? 2ax + 3x^2 + 5 = 0 How would I find a? Would I use 0 = (2)^3 + a(2^2) +5(2) +2 to get a = -5 0 = 2(-5)x + 3x^2 +5 0 = -10x + 3x^2 +5 0 = 3x^2 - 10x + 5 x = (5 +sqrt(10))/3 and (5 - sqrt(10))/3 ? or 0 = ( 2a(2) + 3(2)^2 +5 0 = 4a + 12 + 5 0 = 4a +17 -4a = 17 a...

Homework Statement f(x) = x^3 +ax^2 +5x +2 and has two stationary points, one of which is x = 2. a) Find the other stationary point. b) classify the stationary points using the second derivative test The Attempt at a Solution f '(x) = 2ax + 3x^2 +5 f ''(x) = 2a + 6x 0 = (2)^3 + a(2^2) +5(2)...

No, but how would I do that? It's not required or anything nor is it asked.

Homework Statement Is there another way to do this question? Is this right? L = 50-2x W = 40-2x Height= XHomework Equations // V=L x W x H V= (50-2x)(40-2x)(x) V= (2000 -180x +4x²)(x) V= 2000x -180x² +4x³ V= 4x³ - 180x² +2000x V' = 12x² -360x +2000 X = (360 (+/-)sqrt(360²-4(12)(2000))) /...

X = 2(Vo²Sin a cos a) / g Is this for the entire graph for displacement in X? H = (1/2g) Vo² Sin²a Is this for the height of the maximum height for the graph? ( 1/2g ) Vo²Sin2a = 0 Does this find the maximum height for the graph? t = VoSin a / g Is this for Time at V = 0? or max height? t...

Y(t) = VoyT - (gt² / 2 ) H = (1/2g) Vo² Sin²a ( 1/2g ) Vo²Sin2a = 0 X = 2(Vo²Sin a cos a) / g Vy(t) = Voy - gt 0 = Voy - gt t = Voy / g t = VoSin a / g

So did the ball go up 4.00 m/s for 5 secs or go up the hill for 20 meters and then started to roll down at 6 m/s?

A ball rolls at an initial velocity of 4.00 m/s up a hill. 5 seconds later it is rolling down the hill at 6.0 m/s. <---- What does the question mean? Did the ball roll up for 5 seconds and then started rolling down? Find its acceleration Find its displacement at 5.0s