Maximum Volume of an Open Top Box

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SUMMARY

The discussion focuses on maximizing the volume of an open-top box defined by the dimensions L = 50 - 2x and W = 40 - 2x, where the height is x. The volume formula V = (50 - 2x)(40 - 2x)(x) simplifies to V = 4x³ - 180x² + 2000x. Participants explore alternative methods to find the maximum volume without using derivatives or graphing techniques, emphasizing that these methods are not necessary for solving the problem.

PREREQUISITES
  • Understanding of polynomial functions and their properties
  • Familiarity with volume calculations for three-dimensional shapes
  • Basic knowledge of optimization techniques in calculus
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Research methods for finding maxima and minima without calculus
  • Explore the application of the AM-GM inequality in optimization problems
  • Learn about the geometric interpretation of volume maximization
  • Investigate numerical methods for solving polynomial equations
USEFUL FOR

Students studying calculus, educators teaching optimization techniques, and anyone interested in practical applications of polynomial functions in real-world scenarios.

Carl_M
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Homework Statement


Is there another way to do this question?
Is this right?

L = 50-2x
W = 40-2x
Height= X

Homework Equations



//

V=L x W x H
V= (50-2x)(40-2x)(x)
V= (2000 -180x +4x²)(x)
V= 2000x -180x² +4x³
V= 4x³ - 180x² +2000x
V' = 12x² -360x +2000
X = (360 (+/-)sqrt(360²-4(12)(2000))) / 2(12)
X = 7.36...

How would I do this without using f ' ( x ) ? nor graph it

The Attempt at a Solution

 
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Are they asking you to do it without taking the derivative and setting it equal to zero?
Graphing is never necessary. Just for convenience.
 
No, but how would I do that?

It's not required or anything nor is it asked.
 

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