Recent content by cascadeless
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Understanding Negative Feedback Systems: Equations, Dynamics, and Activation
No one any suggestions or ideas/thoughts? :)- cascadeless
- Post #2
- Forum: Biology and Chemistry Homework Help
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Understanding Negative Feedback Systems: Equations, Dynamics, and Activation
We express such equations by $$\frac{dx}{dt} = \beta - \gamma \cdot x$$, t denotes the time. In this case, γ depends on x, thus the dynamic equation should probably be: $$\frac{dx}{dt} = \beta - \gamma(x) \cdot x$$ 1. Setting the equation to 0 leads to two different cases: If x < K: xST = γlow...- cascadeless
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- Feedback Negative System
- Replies: 1
- Forum: Biology and Chemistry Homework Help
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Compute steady states of gene expression
Ah, now I see, later I have $$x min^{-1} \cdot y min$$ and it cancels to x*y. Thank you!- cascadeless
- Post #16
- Forum: Biology and Chemistry Homework Help
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Compute steady states of gene expression
Meaning that I should calculate further with α = 10, right?- cascadeless
- Post #14
- Forum: Biology and Chemistry Homework Help
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Compute steady states of gene expression
I have just a stupid other question, which is not worth to create a new thread. It is just a notation issue and I'm not quite sure, it says: "The degradation rate of an activator is $$\alpha = 10min^{-1}$$" So, do I have to calculate further with alpha=10 or alpha=1/10? Actually I was pretty...- cascadeless
- Post #12
- Forum: Biology and Chemistry Homework Help
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Compute steady states of gene expression
Thank you guys so much, you helped me a lot!- cascadeless
- Post #11
- Forum: Biology and Chemistry Homework Help
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Compute steady states of gene expression
Okay, thank you very much. Now I have another question due to 3: "At t=3 hours the bacteria gets a signal that cases the protein X to become unstable with half-life of 10 min." I would say that alpha changes when the protein becomes unstable. Does that mean, that alpha is now (1/20 was the...- cascadeless
- Post #8
- Forum: Biology and Chemistry Homework Help
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Compute steady states of gene expression
I am still confused with the description: "A bacteria that normally divides every 20 minutes express gene X. The production rate of protein X is 5nM/min. The protein is stable and does not degrade." When a bacteria B express a gene X, then is B a repressor of X, no? Shouldn't then be the...- cascadeless
- Post #6
- Forum: Biology and Chemistry Homework Help
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Compute steady states of gene expression
Unfortunately, I am not able to edit my post above, and I've noticed another bug in the degradation/dilution rate formula, I am sorry. Here are the correct equations: Homework Equations $$\beta ... \text{production rate}$$ • Degradation/dilution rate in units of 1/time $$\alpha = \alpha_{dil}...- cascadeless
- Post #5
- Forum: Biology and Chemistry Homework Help
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Compute steady states of gene expression
Thanks a lot for your reply. Oh yes, Y is X, sorry. The book denotes it as Y and the assignment as X. The second steady state would then be 1200, however, I'm not sure if my simulation is ok, looks weird to me. To be honest, I am not really able to provide you more background, it is just a...- cascadeless
- Post #3
- Forum: Biology and Chemistry Homework Help
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Compute steady states of gene expression
Homework Statement A bacteria that normally divides every 20 minutes express gene X. The production rate of protein X is 5nM/min. The protein is stable and does not degrade. What is the concentration of X in the steady state?The same bacteria enter into a stress state at t=0 for 3 hours...- cascadeless
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- Expression Gene Gene expression States Steady
- Replies: 15
- Forum: Biology and Chemistry Homework Help