Recent content by Cefari
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Finding the Rate of Change of Water Level in a Conical Tank at a Specific Depth
Alright so here's what I did, I don't have an answer key so not sure if it's 100% right. 1) I rewrote r in terms of h as r/h = 10/12 so r = 5h/6 2) I substituted that in for r in the original and simplified getting a new equation of (25h^3 pi)/108. 3) I derived with respect to t and got...- Cefari
- Post #5
- Forum: Calculus and Beyond Homework Help
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Finding the Rate of Change of Water Level in a Conical Tank at a Specific Depth
I don't quite see how to do that, although it does look similar to something my teacher may of gone over in class. I'm thinking the similar triangles use radius and height as their legs, so the larger triangle I guess would be width of 5 and a height of 12 and the similar triangle would be a...- Cefari
- Post #3
- Forum: Calculus and Beyond Homework Help
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Finding the Rate of Change of Water Level in a Conical Tank at a Specific Depth
Homework Statement A conical tank (with vertex down) is 10 feet across the top and 12 feet deep. If water is flowing into the tank at a rate of 10 cubic feet per minute, find the rate of change of the depth of the water when the water is 8 feet deep. The Attempt at a Solution First I...- Cefari
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- Change Cone Rate Rate of change
- Replies: 5
- Forum: Calculus and Beyond Homework Help
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Finding Charge on a Cube Corner
Homework Statement Given a cube with equal charges on all corners save one, find the charge on the origin. http://img79.imageshack.us/img79/4968/cubekg7.jpg Homework Equations F = kQ1Q2The Attempt at a Solution My current idea is splitting up the magnitude of all charges on the origin into...- Cefari
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- Charge Cube
- Replies: 1
- Forum: Introductory Physics Homework Help
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Current in a Complicated Circuit
Thank you both for the help. :approve:- Cefari
- Post #5
- Forum: Introductory Physics Homework Help
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Current in a Complicated Circuit
Alright so my reworked solution is as follows: Current of R1 = 1/2 Current of R2 so, Current of R1 = .25 A Current Through R3 = Current through R1 + R2 so, Current of R3 = .75 A Voltage through R2 = .5(8) = 4v Voltage through R3 = .75(20) = 15v Battery Voltage = 4v+15v = 19v V = IA...- Cefari
- Post #3
- Forum: Introductory Physics Homework Help
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Current in a Complicated Circuit
Homework Statement In the figure, the current of the circuit in the 8 ohm resistor is 0.5 A. What is the current in the 2 ohm resistor? Figure http://img181.imageshack.us/img181/5576/helpfk7.jpg I'm trying to solve for the current in a complicated circuit. I'm given R1 = 16ohms, R2 =...- Cefari
- Thread
- Circuit Current
- Replies: 4
- Forum: Introductory Physics Homework Help