Finding Charge on a Cube Corner

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SUMMARY

The discussion centers on calculating the electric field at the origin of a cube with charges placed at its corners, with one corner left uncharged. The participants utilize Coulomb's Law, represented by the equation F = kQ1Q2, to analyze the contributions of the charges. The initial attempt involved breaking down the charge contributions into their X, Y, and Z components, leading to a preliminary conclusion of a total charge of +4 at the origin. However, the importance of vector addition and the inverse square law in calculating electric fields is emphasized, indicating that the initial approach may be flawed.

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  • Coulomb's Law (F = kQ1Q2)
  • Vector addition of forces
  • Understanding of electric fields
  • Basic geometry and the Pythagorean theorem
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  • Learn about the inverse square law in electrostatics
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Students in physics, particularly those studying electrostatics, as well as educators and anyone interested in understanding electric fields in three-dimensional charge configurations.

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Homework Statement


Given a cube with equal charges on all corners save one, find the charge on the origin.
http://img79.imageshack.us/img79/4968/cubekg7.jpg

Homework Equations


F = kQ1Q2

The Attempt at a Solution


My current idea is splitting up the magnitude of all charges on the origin into their X,Y, and Z components.

Because all magnitudes are formed with right triangles I can use pythagorean theorem to solve for the components and I get:

Q1: +1 in the X
Q2: +1 in the Z
Q3: +1 in the Y
Q4: +1 in the X, Z
Q5: +1 in the X, Y
Q6: +1 in the Y, Z
Q7: +1 in the X, Y, Z

So the sum of the magnitudes acting on the origin would be +4 in all directions, and I have a feeling this is wrong.
 
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Hi Cefari! :smile:

I don't understand either the question or your answer. :confused:

Do you mean find the field at the origin?

If you're adding fields, remember that they're vectors (with a direction), and the strength is 1/distance-squared.
 

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