Recent content by CelesteSeven

hah, I believe you mean "Geduld"? I know it does, however, this is due in an hour. I can always go tomorrow and have a TA spell it out for me (and I will do that). It's just a matter of 2 extra points tonight. I won't get them, but eh. Maybe I can make up for it on the midterm.

thanks for all your help, but I'm afraid I still don't understand. it's frustrating enough, so I'm giving up on it. thanks everyone for devoting your time. i appreciate it, and I think I understand the problem much better, even if I don't get it fully still.

BLAH! THAT COS25 SHOULD BE 65. I only typed that error on here, not in my calculator. In my calculator, i had 65.

how about this:

Assuming "E" is the sigma... EF = T - 665 = 0 (yes?) The tension has both vertical and horizontal components, which add up to 665. But where are the components? I mean, the rope in the problem should be the hyp of the given triangle, right? That's what I keep assuming. But i yield the same...

No, I don't think we have to do it using trig. But is there another way? Just adding x and y components? I yield always the same incorrect answers. Not to mention the german midterm tomorrow. yikes, I am appreciating the help tonight!

i do know about the sum of forces. and I understand x and y components and how they are separate. i do not know how to resolve forces... or even what that means (and I go to class and pay attention, as well). Our TA is a bit sloppy when it comes to giving us the correct problems though...

no, I don't. it's an online homework. I'd like to get the answer right before 11:30pm est (tonight) because that's when it's due. i can always go tomorrow (before the exam) and have the TA help me and explain it to me, but that doesn't do good for me point wise (and I really need them) and I...

anyone? time is running out:frown:

we haven't done much with tenstion, Cristo, so I'm still as confused. all I can think of to do to draw the forces according to the person is to draw a straight line down from her (her force of weight) being 665N. But then I have a triangle with a another line drawn down (which seems obsolete)...

A mountain climber, in the process of crossing between two cliffs by a rope, pauses to rest. She weighs 665 N. As the drawing shows, she is closer to the left cliff than to the right cliff, with the result that the tensions in the left and right sides of the rope are not the same. Find the...

homework help! eek! A mountain climber, in the process of crossing between two cliffs by a rope, pauses to rest. She weighs 665 N. As the drawing shows, she is closer to the left cliff than to the right cliff, with the result that the tensions in the left and right sides of the rope are not the...

I've done this thus far: Rx = .19(cos 57) +.11(cos0) = .21348N Ry = .19(sin 57) + .11 (sin 0) = .1593N Ax = .21348/2.9 = .07361 Ay = .1593/2.9 = .0549 then I do the tan-1 (.0549/.07361) which yields the wrong answer. Any suggestions?

A duck has a mass of 2.9 kg. As the duck paddles, a force of 0.11 N acts on it in a direction due east. In addition, the current of the water exerts a force of 0.19 N in a direction of 57° south of east. When these forces begin to act, the velocity of the duck is 0.13 m/s in a direction due...