Recent content by cgstu

thanks tiny tim, so if I understand correctly now the answer should be three?

I guess that's what I am not sure of. I know that if i=j then the delta function =1 else delta =0 so my thinking was δ11δ11 + δ12δ11 + δ13δ11 + δ21δ11 + δ22δk11 + δ23δ11 + ... where only when the indices matched is the entire function = 1 δ11δ11, δ22δ11, δ33δ11... etc This...

If given δ_ijδ_kk what would the expansion of that be? I thought it was nine but have been told that is incorrect. I know that i=j =1 else zero so I thought that the δ_kk would equal 3 times 3 from the expansion of δ_ij but that isn't the answer