Recent content by chaostheory1

Or am I doing this wrong... Since the force that stopped the car was frictional; won't I have to calculate the frictional force using the Newton weight of the car? And use the frictional force in the KE and Work formulas?

Ok, KE=(.5)(mv^2) KE=(.5)(1000 kg * (29 m/s)^2) KE=420,500 N W=KE How can I possible have 420,500 N of work done by brakes?

I have honestly been trying to figure this problem out for over an hour now, and every time I try to solve for KE, I get a ridiculously high number. Homework Statement A race car having a mass of 1000 kg was traveling at high speed on a wet concrete road under foggy conditions. The tires on...