Recent content by Charles49

by guy ben-yosef and Ohad ben shahar

Here is a good paper: A Tangent Bundle Theory for Visual Curve Completion

Thank you very much.

Hi Stephen, I have a single image. It is computer generated from a series of images. Since my background is not in computer science, could you please give me a few keywords that I can google to make my search for possible answers more effective? I am looking up training set now. Charles

I am supposed to have an image consisting of overlapping curves. What I have is an image where the curves are missing certain segments of them. However with the human eye we can tell that certain segments are part of the same curve. (see attached figures). I want to know how I can write a...

HallsofIvy, What a simple solution! Thanks

If we want to solve $$f(x)=0$$ we can re-write the equation as $$g(x)=x$$ and use the fixed point method, i.e, $$x_{n+1}=g(x_n)$$ starting with a guess $$x_0.$$ I was wondering if something similar can be done with $$\Lambda(x,y)=h(x,y).$$

Thanks AlephZero, I am going to learn about Crouts version.

Thanks DonAntonio

Let $$A$$ be the $$n\times n$$ matrix: \begin{equation} A= \begin{bmatrix} % or pmatrix or bmatrix or Bmatrix or ... 2 & 1&\dots & 1 & 1 \\ 1 & 2&\dots & 1 & 1 \\ \vdots&\ddots & \ddots & 2 & 1 \\ 1 & & \dots & 1&2 \\ \end{bmatrix} \end{equation}...

I don't think this integral converges. Here's my analysis: $$ \iint _{\mathbb{R}^2}\!{\frac {{{\rm e}^{i \left( x+y+\sqrt {k-{x }^{2}-{y}^{2}} \right) }}}{\sqrt {k-{x}^{2}-{y}^{2}}}}{dx}{dy} =\iint_{\mathbb{R}^2}\!{\frac {\cos \left( x+y+\sqrt {k-{x}^{2}-y^2} \right) }{\sqrt...

How is this a Fourier Transform?

1. Go here: http://en.wikipedia.org/wiki/Riemann_integral and look under: Riemann Sums. You'll see that you need a width. So I don't think you can write it as a Riemann Integral. 2. The slope can't be zero because the tangent line never intersects the x-axis and the concept of angle is...

Let's say the end points are a and b. Let $$x_0=a, x_1=a+h, x_2=a+2h\cdots, x_n=a+nh=b$$ where $$h=\frac{b-a}{n}.$$ The angle as indicated in the diagram is $$\pi-\arctan(f'(x))-\arctan(f'(x+h)).$$ So you have to...

Are you interested in the curvature of the function? If so there are formula for finding curvature.