How to generalize the fixed point iteration

[Charles49]

If we want to solve $$f(x)=0$$ we can re-write the equation as
$$g(x)=x$$ and use the fixed point method, i.e, $$x_{n+1}=g(x_n)$$ starting with a guess $$x_0.$$ I was wondering if something similar can be done with
$$\Lambda(x,y)=h(x,y).$$

 

[HallsofIvy]

Yes, of course. Just think of (x, y) as a single two dimensional variable, z and solve g(z)= z.

 

[racefan4TX]

Excellent info can be found about these kinds of boards. Thanks folks.

 

[Charles49]

HallsofIvy,

What a simple solution!

Thanks