- #1

Charles49

- 87

- 0

$$g(x)=x$$ and use the fixed point method, i.e, $$x_{n+1}=g(x_n)$$ starting with a guess $$x_0.$$ I was wondering if something similar can be done with

$$\Lambda(x,y)=h(x,y).$$

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- Thread starter Charles49
- Start date

- #1

Charles49

- 87

- 0

$$g(x)=x$$ and use the fixed point method, i.e, $$x_{n+1}=g(x_n)$$ starting with a guess $$x_0.$$ I was wondering if something similar can be done with

$$\Lambda(x,y)=h(x,y).$$

- #2

HallsofIvy

Science Advisor

Homework Helper

- 43,021

- 970

Yes, of course. Just think of (x, y) as a single two dimensional variable, z and solve g(z)= z.

- #3

racefan4TX

- 1

- 0

Excellent info can be found about these kinds of boards. Thanks folks.

- #4

Charles49

- 87

- 0

HallsofIvy,

What a simple solution!

Thanks

What a simple solution!

Thanks

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