If we want to solve $$f(x)=0$$ we can re-write the equation as(adsbygoogle = window.adsbygoogle || []).push({});

$$g(x)=x$$ and use the fixed point method, i.e, $$x_{n+1}=g(x_n)$$ starting with a guess $$x_0.$$ I was wondering if something similar can be done with

$$\Lambda(x,y)=h(x,y).$$

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# How to generalize the fixed point iteration

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