Recent content by cheese_whizz

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    Conservation Of Energy With Friction

    excellent :) Thanks again for all your help
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    Conservation Of Energy With Friction

    hmm, i did make a mistake :/ Im getting 4.114 as acceleration now which seems correct M x a = F 100 x 4.114 = 411.4N Force - resistive force = F 1000N – 588.6 = 411.4N So i think I got there :) Would this be correct for the D'alembert principle method? Thanks again :)
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    Conservation Of Energy With Friction

    hi, Thanks for taking the time to respond. I've used this equation before but the lecturer never told me it was kinematics :/ is everything correct now? thanks again.
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    Conservation Of Energy With Friction

    Homework Statement Hi, I am having trouble with this problem. I'ld be very grateful if anyone could help me :) I've only done it with the conservation of energy way because I am not too sure how to go about it with the D'alembert principle. A Car with a mass of 100kg is pulled along a...
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