Recent content by Chief17

Thanks for the reply. Not sure what you mean by prefactor. Would I just multiply the albedo times a value (i.e. x) and then solve for x? So: 300=5778((1-0.2x)/4)^0.25(6.96*10^8/(1.5*10^11))^0.5 ----> x=-1.75

I have a three part question: Background: For a planet on an orbit with semi-major axis a and eccentricity e, the distance of closest approach to the Sun is r = a(1 − e) and the farthest approach is r = a(1 + e). (1) Assuming an albedo A = 0.2, estimate the temperature on Earth in equilibrium...