Recent content by Christian121

Ok got part A I believe now. It's -Q/2*A. Thanks for your help. I got the rest of the parts on this problem right as well.

Ok thanks , er dq = λ*dx? :P. I'll figure it out eventually.

Homework Statement A thin rod lies on the x-axis with one end at -A and the other end at A, as shown in the diagram. A charge of -Q is spread uniformly over the surface of the rod. We want to set up an integral to find the electric field at location ‹ 0, y, 0 › due to the rod. Use the...