Recent content by chriszollman

2.1 x 10^3 1.9x10^3 so 2100 n 1900 s0 2100-1900= 200??

so would it be 200 N = 1200kg X A. v I tried that and i was told i was wrong.

I have a worksheet I received for make-up since I was absent. It is really hard since I miss the lesson. All the problems are similar, but I do no know where to start. Here is a sample problem. Will someone show me steps on how to do it? A boat moves through the water with two forces acting...

Its the one on the cross bar

Is it Vx=Vxi=Vxf so is it 31?

Vi= 31 Angle-50 X=36 Y=13.7? I think. Where do I go from there? Thanks

Sorry. First time in the threads I got 13.7 for the m for the change in X. I don't no where to go past that. What should I do.

Can someone work show me how to work this? I am very confused. 1. A place kicker must kick a football from a point 36.0 m (about 40.0 yd) from the goal, and the ball must clear the crossbar, which is 3.05 m high. When kicked, the ball leaves the ground with a speed of 31.0 m/s at an angle of...