What is the acceleration of the 1200 kg boat?

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To find the acceleration of a 1200 kg boat experiencing a forward push of 2100 N and a resistive force of 1900 N, first calculate the net force, which is 200 N. Using Newton's second law, the acceleration can be determined by dividing the net force by the mass of the boat, resulting in an acceleration of approximately 0.167 m/s². For further calculations, such as distance traveled in 10 seconds and final velocity, apply the basic equations of motion. The initial conditions are crucial for solving these equations accurately. Understanding these steps is essential for tackling similar problems effectively.
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I have a worksheet I received for make-up since I was absent. It is really hard since I miss the lesson. All the problems are similar, but I do no know where to start. Here is a sample problem. Will someone show me steps on how to do it?

A boat moves through the water with two forces acting on it. One is a 2.1 103 N forward push by the motor, and the other is a 1.9 103 N resistive force due to the water.
(a) What is the acceleration of the 1200 kg boat?
m/s2
(b) If it starts from rest, how far will it move in 10 s?
m
(c) What will its velocity be at the end of this time interval?
m/s
 
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You need the basic equation of motion for an object:

\Sigma F_i = m a_i

In other words, in each coordinate direction, the sum of forces on an object is equal to the mass of the object times acceleration (i.e. second derivative of x with respect to t). Integrate twice to get x(t), evaluate the initial conditions from the problem statement, then solve from there.
 
so would it be 200 N = 1200kg X A. v I tried that and i was told i was wrong.
 
2.1 x 10^3 1.9x10^3 so 2100 n 1900 s0 2100-1900= 200??
 
I figured out what you meant. Yes: The net force is 200 N and the acceleration will be given via Newton's law, just like you wrote in post #3.
 
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