Recent content by chrononaut 114

Hi Orodruin, I forgot to ask another question (much simpler than before) regarding a different exam problem, and I thought I'd just write it here to save some time... So when writing the kinetic energy for the Lagrangian ##( L = T - V )## of this system (diagram below), I got a little confused...

Ok, yeah that makes sense now, thanks

I see, that's fair, my apologies. I didn't know that was a forum rule and will read the rules more closely now. I've actually been studying for it throughout the past few weeks but since this is probably one of the hardest subjects I've encountered I've been panicking, and with some other exams...

Thanks for your response. So I tried a couple different ways and they all were also convoluted also; basically I don't really know how to properly implement what you're explaining. I'm just still confused as to what would be the most efficient generalised coordinates relative to the fixed point...

So I've had another thought about it.. so for the (two) generalised coordinates, what about ## \theta = \theta(t) ## being the angle that the spring makes with the horizontal x-axis, and ## \phi = \phi(t) ## the angle between the line that joins from the origin to mass m and the vertical y axis...

Homework Statement The Attempt at a SolutionSo I first tried by saying consider a time t in which mass m is directly above the origin O. I.e., mass m at the Cartesian coordinate (0, 4l/3). I wrote a = a(t) as the extension function of the spring, which has 0 natural length. So, I applied the...

I just found this version of an expression for the absorption coefficient: (from: http://file.scirp.org/Html/2-7700668_17248.htm) -But it doesn't specify what K is, rather it just says that it is a constant, so not really sure what to do with that -Here E_g is the bandgap energy, as per...

Cheers. I found this expression for the absorption coefficient: (from: http://www.pveducation.org/pvcdrom/absorption-coefficient) It can easily be converted to a function of frequency by using λ = c/f . But, here, 'k' is referred to as the 'extinction coefficient', which I couldn't find an...

Thanks for the response, really appreciate it. Ok that makes sense, I think; so if it were an indirect bandgap it wouldn't 'line up' with the absorption peak since it has a different momentum value or something like that? So, I think I see a strong absorption at that wavelength in the form of...

(urgent) Hi, This question was apart of an assignment sheet that I was given in 'Experimental Physics III' after having completed and obtained data for the practical called 'The Bandgap Energy of Semiconductor ZnSe'. Cheers Below is some screenshots of the (Matlab-processed) data we obtained...