cianfa72's latest activity

The frame in which you are at rest right now is not inertial. You are stationary in this frame--because you are at rest in the frame...

No. By lifting one of them in the fourth dimension out of the 3-sphere in R^4, they can be separated.

Ok, furthermore such Hermite functions (that are defined on the entire R, are measurable w.r.t. the Lebesgue measure on R and the square...

Sorry, I'm not sure what that link refers to. Does the part in bold above refer to Hermite functions ?

Ok, so in the context of Newtonian physics let's pick the frame in which I am at rest. What if this isn't inertial? To do dynamic w.r.t...

Apart from this, can we explicitly exhibit an Hilbert basis (i.e. a maximal orthonormal set) consisting of square integrable functions...

The idea could be "lift" one the two linked loops in R^3 along the fourth dimension to separate it from the other. Yes, move it along...

@Hornbein Intuitively, in Euclidean 3 space, two non-intersecting closed loops are linked if they cannot be separated without...

Sorry, I've not idea for this.... :rolleyes:

Can you explain why they can always be separated in the "ambient" ##\mathbb R^4## ?

I'm not sure whether what follows fits better in a math subforum. Take the Hilbert space of square integrable functions of one variable...

Ah ok, so here we are taking just a kinematic viewpoint/description, no dynamic is involved.

Yes, however the person who says "I'm stationary" must measure for themself zero proper acceleration.

Yes, however to me this is a bit confusing. In your example, the particle (the quantum system) is in a quantum state in the relevant...

In the context of quantum physics the state of a quantum system is represented by a vector, say ##\ket \psi##, in the...