Recent content by circuit_boy

I see, the answer would be 5 then? Thank you for your input, try to have a look at question 2 too, thank you!

Since Q/T = I We can say that taking the derivative of Q with respect to T will yield I, which is actually the gradient of Q and T, or of the graph. From t=2 till t=4, gradient is negative, hence yielding a negative value. Are there anymore errors that you have spotted in the solution?

Homework Statement Question 1: http://img690.imageshack.us/i/79806671.jpg/ Question 2: http://img833.imageshack.us/i/48920688.jpg/ Homework Equations V=IR, P=I^2R The Attempt at a Solution Answer to Question 1: http://img831.imageshack.us/i/imgmp.jpg/ Answers to...