Recent content by civil_dude

The problem I see with this is the end reactions/support. I would consider a bow truss, not inverted. The thing to remember in trusses is that the further away the top chord is from the bottom chord, the more resistance you will have to bending stresses. Also, to prevent buckling of the...

The term chord is typically used for trusses. You have a top chord, and a bottom chord. The are different from the diagonals, or struts.

I believer the compressive force is constant from the tension connection to the wall. Thus a tapered member would not get you much additional strength, or just shift the failure point to the narrow end. You simply need to beef up the compressive members to withstand a higher force. Perhaps...

I have looked at this, and plugged b/c into excel and it works for 5 different b and c constants. Thus for me, b/c is correct.

It will be a very long semester for you is you don't learn dimensional analysis. I would spend some extra time on it or get some tutoring. You might try leaving out the numbers at first and just examing the units to make sure that what you want to cancel does. For instance: km/hr * m/km *...

I thought this was a Differential Equations kind of Calc. I couldn't do one now but I remember these types of questions in DE.

Think about a water, since it is incompressible and air is not. The principle is continuity of flow, i.e. for steady state flow mass in = mass out along any portion of the pipe or reach. So since the building reduces the area available for flow, to remain in steady state, the velocity has to...

For your first question, yes, it is that simple, but pay attention to your units. For the second question, you are correct and should assume that continuity holds. For the third question think about it. The water is in static equilibrium right? What does that tell you about the force on...

I agree that the term 'dimension' is not the same as units. The dimensions for angular displacement would be angle; angular velocity would be angle per unit time; and angular velocity would be angle per unit time per unit time. The working unit for angle is radians, which is unitless. The...

I too would recommend the general approach. I did that in civil and am glad I did. You will get your specialised education once you start working. You will have a wider subject background which gives you more options in employment.

Where I went to school, the first two years were pretty much the same for the physics and engineering core subjects. The last two years were where everyone went different directions. The last two years for me focused on engineering in my chosen field with relevant courses.

One example could be a simple as opening a jar.

A simple equation for power, P, is: P = Q * ((gamma)force density) * h I get 70.7 W Of course this doesn't account for any parasitic losses.

I agree with Andrew, that the sub's internal pressure should cancel out with the atmospheric pressure. Is there something amiss?

This is a structural analysis, which really can't be taught here. You can get a statics book and study how to conduct such an analysis. Also, for your logging application there are many variables that will affect the answer, such as wind and ground conditions and the actual tree weight and...