Recent content by cjhseeker

Remaining confusion about problem In that case, the integral is equal to the current enclosed by the surface, multiplied by the constant (mu). Is the value of the current enclosed 2A or 1A? This is a bit unclear to me due to the nature of the Amperian surface. Thank you for helping.

Homework Statement What is the line integral of B between points i and f in the figure? Homework Equations Ampere's Law: ∫B∙dl = Ienclosed * μ0 note: the integral on the left is a line integral. The Attempt at a Solution I applied Ampere's Law. I know that the contribution...