Recent content by clokey34

Oh right you make it so simple! Thanks. So change in velocity over change in time. Change in time is 0.02sec change before 119.1 -114.2 = 4.9deg 4.9/0.02=245deg change after 123.4 - 119.1 = 4.3deg 4.3/0.02=215deg (245+215)/2= 230deg.sec-1 Accel= change of rate of velocity is (230-245)/2...

Yeah I agree it is 50 cycles a second but then I'm not sure how to apply that?

Homework Statement The following data are for the angular displacement of the knee in cycling measured in degrees. Using radian measure, compute the angular velocity and acceleration when the knee angle is 119.1 degrees. The sampling frequency was 50 Hz. What is a problem you may...

Thank you very much. :) tanθ = y/x was helpful! My answer came close within a degree, but I suppose there was issues rounding, I'll ask my teacher what he wants.

Homework Statement Calculate the knee joint angle based on the XY coordinates of the hip, knee and ankle joint centres. Hip joint(x = 1.0183, y = 0.7959) Knee joint(x = 1.1223, y = 0.5042) Ankle joint(x = 1.0539, y = 0.1081) Homework Equations θjoint = θproximal −θdistal The...