Segment and joint angles problem.

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To calculate the knee joint angle from the XY coordinates of the hip, knee, and ankle joints, the angle can be found using vectors derived from the coordinates. The upper leg vector (KH) and lower leg vector (KA) are defined, and two methods can be employed: using the tangent function or the dot product. The tangent method involves calculating the angles of the proximal and distal segments, while the dot product method uses the cosine of the angle between the vectors. The student found the tangent method helpful but noted minor discrepancies likely due to rounding. Clarification from the teacher on the expected precision is suggested.
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Homework Statement



Calculate the knee joint angle based on the XY coordinates of the hip, knee
and ankle joint centres.

Hip joint(x = 1.0183, y = 0.7959)
Knee joint(x = 1.1223, y = 0.5042)
Ankle joint(x = 1.0539, y = 0.1081)


Homework Equations



θjoint = θproximal −θdistal

The Attempt at a Solution



Biomechanics student here.
Not sure how to do this. I'm sure its a simple one just confused how to start. It is supposed to come out to 29.42 deg. Thanks for your help.
 
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Welcome to PF!

Hi clokey34! Welcome to PF! :smile:

Draw the graph, and use the letters H K and A.

Then the upper leg is KH, and the lower leg is KA, and you want the angle between KH and KA.

So use coordinates to write KH and KA as vectors: KH = H - K, KA = A - K,

Then there's two methods:

i] use tanθ = y/x to get θproximal and θdistal, and then use θjoint = θproximal −θdistal, or:

ii] dot-product KH and KA, and divide by their ordinary product: cosθ = KH.KA/|KH||KA|.

Can you do either of them, or do you need more help? :smile:
 
Thank you very much. :)

tanθ = y/x was helpful! My answer came close within a degree, but I suppose there was issues rounding, I'll ask my teacher what he wants.
 
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