i tried to solve it but I am not sure if it is correct.
ω=2pi/T
360/87x60=2/29
V=ω.r
2/29xr=7800
r=113100m = 113,1km
a = v^2/r = ω^2r (circular motion equations)
(2/29)^2x113,1=78/145 km/sec^2 = 15600/29 m/sec^2
the retro engine deceleration is 6m/sec^2
15600/29-6=15426/29 m/sec^2
is it...
The space shuttle is moving in a circular orbit with a speed of 7.8km/s and a period of 87min. In order to return Earth, the shuttle fires its retro engines opposite to its direction of motion. The engine provide a deceleration of 6m/s^2 that is constant in magnitude and direction. What is the...