Recent content by Clutch Cargo

q is the electric charge of the particle (in coulombs) and E is the electric field (in volts per meter)and it equals...capital E as a scalar! Problem is there is still the question of what the little e is...

Yep, it's advanced physics. And this type of question is not even in the textbook! Another thing that bugs me is the little e. The ONLY mention of the little e in the text is for the rest energy of an electron as being e=.511MeV but looking at the relevant equations I'm given we have mass, time...

I don't know. It is just the "uniform electric field" of unspecified potential. This question is written exactly as it was given to me.

Homework Statement What is the acceleration of a charged particle in a uniform electric field? Assume the particle moves along a straight line parallel to the electric field. Show that a particle starting from rest at x=0 and t=0 the speed and position are given by the following formulas...

Does anyone know how I can get Excel to convert binary to Gray Code and two's complement?

After looking for programs for advanced physics with no luck I decided to write my own. What I have so far is a simple program to calculate relitavistic velocity: (v1,v2) Prgm:Local Input "Enter velocity 1" .v1 Input "Enter velocity 2" .v2 If v1<0 Then (v1+v2)/(1+(v1*v2))»vr...

I was wondering if any of you knew of any programs for the TI-89 that deal with relativity. I've searched with Google but get nothing.

It says that given the initial value of a problem: dy/dx=f(x,y) y(xo)=yo assume that f and df/dy are continuous fuctions in a rectangle R={(x,y):a<x<b, c<y<d} that contains the point (xo,yo). Then the initial value problem has a unique solution #(x) in some interval...

It says: In problem 23-28 determine whether Theorem 1 (existence and uniqueness theorem) implies that the given initial value problem has a unique solution. 23. dy/dx=y^4-x^4 y(0)=7

The existence and uniqueness theorem is exactly what this problem is about. As I have stated the book only gives one example and it is nothing like this problem. I have however looked at the solutions manual for other similar problems and I find in each case the answer book is only concerned...

Thanks Dick. I feel much better that I am not the only one who doesn't understand what is going on. According to the textbook given: dy/dx=f(x,y) and y(xo)=yo if f and df/dy are continuous then the problem has a unique solution. The initial value of y(0)=7 that is given is supposedly the...

Near as I can tell y'=dy/dx=y^4=x^4 is contiuous for y=0 and y=7 and f(x)=integral(y')=xy^4 -(x^5/5) is continuous for all x so IVP has a unique solution at y(0)=7. Does this sound right to anyone?

I know that y(0)=7 is a solution to this IVP because I looked in the back of the book. I don't see how to prove it. My textbook only has one example IVP and it is nothing like this.

Homework Statement I'm having problems with this IVP dy/dx=y^4-x^4 and y(0)=7 I know the answer is yes but I just don't see how to get it. Homework Equations The Attempt at a Solution

I have a problem in my D.E. class that is driving me nuts. Two drivers, A and B are in a race. Beginning from a standing start they both proceed at a constant acceleration. Driver A covers the last 1/4 of the distance in 3 seconds. Driver B covers the last 1/3 of the distance in 4 seconds...