Recent content by Cole07

ok i got is 7.920000002m THANK YOU!

i was thinking that its speed would be less because it is lighter?

ok can i use the formula v=square root of 2(9.8)(1.98) ? and then i need to solve for the mass but i don't recall an equation i can use to find mass since i don't have momentum

how do i do that though if i don't have any number for mass the only number i have is the height of 1.98 m i wasnot given any other numbers?

this is probably the simplest question on this assignment and i don't get it:cry:

i did realize it but i just didn't pay any attention to it on this problem thank you for pointing that out.

Homework Statement A stone of mass 'm' is dropped from rest at a height of 1.98 m. From what height would a stone of mass 'm/2' have to be dropped to have the same momentum upon striking the ground? Homework Equations ? The Attempt at a Solution i don't understand 'm/2'...

ok i see so instead of what i did first it would be: 1.2*15=18 15*.6=9 9*1.2=10.8 10.8+18=28.8 28.8/9000= 0.0032s

do you mean 15m/s

is that the error in line 2?

the 80% is an example from how i was told to do it my percent is 60% i forgot to fix that is that the problem with line two you are talking about? i'll edit it right now.

Homework Statement A 1.2- kg hammer hits a nail at a speed of 15 m/s and rebounds at 60 percent of that speed. The resisting force of the nail is 9000 N. Approximately how long is the hammer in contact with the head of the nail? Homework Equations P=mv Pf-Pi=Ft The Attempt at a...

so it would instead be 909.516396+0.30=909.816396 and then multiply this by 2.6 which would be 2365.52263J ?

My answer still seems to be wrong and I've check my math a few times could someone possibly tell me what i have done wrong please?

could someone please tell me if I'm on the right track.