The problem involves determining the height from which a stone of mass 'm/2' must be dropped to achieve the same momentum as a stone of mass 'm' dropped from a height of 1.98 m. The discussion centers around concepts of momentum and kinematics.
Participants are actively engaging with the problem, raising questions about the necessary equations and the relationships between mass, speed, and momentum. Some guidance has been offered regarding the use of kinematic equations and the implications of mass on speed.
Participants note the lack of explicit mass values and express confusion over how to proceed with the calculations based solely on the given height.
No. The second mass has half the mass of the first mass. What is the momentum of the first ? You'll need to find its speed.Then proceed to work on the momentum of the second mass.Cole07 said:
use m for the mass of mass1, and use m/2 for the mass of mass 2. That will work. Now you have a distance but not a speed. Use one of your motion equations from kinematics that solves for the speed as a function of the height. Are you familiar with these equations?Cole07 said:
Yes for the velocity of the first mass. You don't have to solve for the mass. It is given. the mass is 'm'.Cole07 said: