Recent content by Colts

So what I've figured so far is s*Y(s)-25* inverse laplace of {Y(s)G(s)} = 1 How can I solve for Y(s) when it is in the inverse laplace transform?

if f and g are piecewise continuous then the convolution of the two is \int f(\tau)g(t-\tau)d\tau from 0 to t or \int f(t-\tau)g(\tau)d\tau from 0 to t and F(s)G(s)=Laplace Transform of the convolution of f and g in this case y(t-w) is f(t-\tau) and e^{-10w} is g(\tau) So now...

I am really confused where to start with this problem. I know about convolutions somewhat. We have done them a little. Where is a good place to begin with this problem?

I messed up. I read the problem as the wire is 5 cm long, but I think we treat this as the wire is infinite and the cords holding the wire is 5 cm long. So now I can use B=(μ*i)/(2∏*D) where D is the distance from the wire and μ is the magnetic constant in equations. Also, this is the equation...

L is the length of the wire and B is the magnetic field

Homework Statement In the figure, two wires are hanging parallel to one another. Each wire hangs 7 degrees from the vertical on 5 cm long cords. If the wires weigh 35 grams per meter, how much current do they carry? http://www.usi.edu/science/physics/pickett/206/15p2f1.jpg Also, the current...

Ok, I messed up the area so without the 2 in there I get current density to be 26.9 C/M Rude Man: I used the flow rate to get the current.

I got density of water to be 1000 kg/m^3 and 1 mole for every 18 grams of water. So I did: \frac{1000 kg}{m^{3}} 2∏ (.04m)^{2} \frac{1 gram}{1000 kg} \frac{1 mole}{18 grams} \frac{6.022x10^{23}}{1 mole}1.6x10^{-19}C So I got 53.81 C/M Then I multiplied this by 3.5 M/s to get 188.35 C/s

Homework Statement (a) Water flows through a pipe of radius 4 cm at a rate of 3.5 m/s. Suppose each water molecule is singly ionized (highly unrealistic). What is the electric current density associated with the flow of these ions? b) What is the electric current in the pipe? Homework...

I'm a sophomore civil engineering student in strength of materials class and have to come up with a project. The project was take something and due a compression, tensile, deflection, etc. test. My first thought was to do something with self-consolidating concrete, which I heard about last...

Homework Statement (a) The current through a wire is a steady 2.5 amps. How much current passes through it between t = 0 seconds and t = 4 × 10^-4 seconds? For this one I thought it would be 2.5( 4 × 10^-4), but it says how much current and I thought current was a rate. So what does the...

Homework Statement In the figure the rod has a charge density of ßx, where x=0 is the left end of the rod, etc. Find the electric potential energy of the point charge q a distance a from the end of the rod and lying along the rod's axis...

Is it as easy as adding the two V's up? Like V_{1}+V_{2}=V So the answer would be V=\frac{q}{2\pi\epsilon a} Does direction not matter?

Homework Statement Calculate the electric potential at (a) point P in the first figure, and (b) point M in the second. http://www.usi.edu/science/physics/pickett/206/5p3f1.jpg Homework Equations V=\frac{q}{4\piεr} E=\frac{q}{4\piεr^{2}} The Attempt at a Solution I'm not sure if E...

\int\frac{βxdx}{2πrε} x is the distance does that look right? and the integral would be from a to b