Calculate the voltage at a point

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    Point Voltage
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Homework Help Overview

The discussion revolves around calculating the electric potential at specific points based on provided figures and equations. The subject area includes concepts from electrostatics, particularly electric potential and electric fields.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the necessity of the electric field in calculating voltage, with one participant attempting to use vector components of the electric field. Others question whether the potentials can simply be added together and discuss the scalar nature of electric potential.

Discussion Status

Some participants have provided guidance on the approach to calculating voltage, indicating that the electric field may not be necessary. There is an ongoing exploration of how to combine the potentials from different sources, with some clarity on the scalar nature of potential being established.

Contextual Notes

Participants are navigating the definitions and relationships between electric potential and electric field, with some uncertainty regarding the assumptions about direction and the method of combining potentials.

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Homework Statement


Calculate the electric potential at (a) point P in the first figure, and (b) point M in the second.
http://www.usi.edu/science/physics/pickett/206/5p3f1.jpg

Homework Equations



V=\frac{q}{4\piεr}
E=\frac{q}{4\piεr^{2}}

The Attempt at a Solution


I'm not sure if E is really necassaryt, but I wasn't sure how else to get the direction right. So I did the vector stuff with E and got
\vec{E}=<0,\frac{-q}{2\pi\epsilon(.75)a^{2}}>

Now I'm stuck and don't know how to get to voltage
 
Last edited by a moderator:
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You don't need the electric field - just use the definition of V.
 
Is it as easy as adding the two V's up?
Like
V_{1}+V_{2}=V
So the answer would be
V=\frac{q}{2\pi\epsilon a}

Does direction not matter?
 
Yes, you just add them up.
The potential is a scalar, not a vector, so it doesn't have a direction.
 

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