Recent content by confusedperson

Huh. That was not expected...I simply have not come across a problem of this type before. There goes at least 10 marks for my final exam. However, lesson learnt. Thank you guys for enlightening me on this new knowledge.

Thank you. I'm not entirely sure how that works but I assume I have to add 4cm of water back into the final gauge pressure?

Sorry I do not understand what is the real balance equation...

I don't know what I did wrong for this question, but I assume something is wrong as my solution is extremely simple and this is a 20 marks question... 1. Homework Statement Refer to uploaded image. Homework Equations Pressure = h ( density in kg/m^3 ) ( gravitational acceleration) The...

To be honest I think it is just a lucky coincidence that my answer was close to the actual answer, I still don't know how to solve this... I'm assuming it has something to do with the pressure difference between the mercury filled portions of the tubes at 30cm from datum.

pressure at 0.3m from datum, left side: 0.4 * 1000 * 9.81 + 0.3 * 13600 * 9.81 = 3924 + 40024.8 = 43948.8 Pa pressure at 0.3m from datum, right side: 0.8 * 800 * 9.81 = 6278.4 Pa Difference between the 2: 37670.4 Pa Not the exact answer I was given but close enough that i guess it is not too...

I think the solution is to find the pressure difference between (40cm of water +30cm of mercury) and 80cm of oil. Thanks for the help guys.

uh thanks that might be what i have been missing, will attempt again

Now, I assume that the pressure is the same in the oil at the points 70cm above the datum. However how am i supposed to know the distance from the datum to the base of the manometer? Man this question is giving me a headache.

Homework Statement Need to find the pressure difference between the two water pipes. Specific gravity of water = 1000 kg/m^3, specific gravity of oil = 800 kg/m^3[/B] Homework Equations pressure = height * specific gravity * gravitational acceleration The Attempt at a Solution I think that is...