Recent content by Copse

cos(kx) This is my first physics class and our book doesn't mention trig. functions in the section about dimensional analysis. I am just a little confused.

Thank you for answering my question. So, does it just boil down to the equation being correct because y and 2m are both lengths?

Homework Statement Show that this equation is dimensionally correct. y = (2m)cos(kx), where k = 2m^-1 Homework Equations None that I know of. The Attempt at a Solution I don't know why this is correct. I have looked through the chapter and all of the dimensional analysis...